Question

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Q.1..] The length of the minute hand of a clock is 5 cm find the area swept by the minute hand during the time from 4:05 a.m. to 4:40 a.m.​

Answer 1

Answer:

45 (5/6) cm²

Step-by-step explanation:

Time between 4:05 a.m to 4.40 a.m = 35 minutes.

We know that : In 60 minutes, the minute hand of a clock makes one complete round i.e 360°, therefore in 35 minutes it moves through :(360/60) * 35 = 210°.

∴ Area swept by the minute hand during the time from 4:05 to 4:40 = area of sector of circle of radius 5 cm and making an angle of 210° at its centre

= θ/360° * πr²

= (210/360) * (22/7) * (5)²

= (11 * 5 * 5)/6

= 275/6 cm²

= 45 (5/6) cm².

Therefore, the area swept = 45 (5/6) cm².

Hope it helps!

Answer 2

Step-by-step explanation:

1 MIN=6O

FOR 35 MIN

35 * 6=210O

AREA OF SECTOR

O/360 PIE R2

210/360 *22/7*5*5

275/6

45.8CM.SQ