Hello!
Kindly do the middle term split of the above question in full explanation!!
: )
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Answered by
1
bring the linear coefficient to the middel
so
6x2-7x-3
now by mid term factorisation
we have to find a numbers Which When multipled give 6*-3=-18 and on adding gives -7
so they are -9 and 2
so we can write it as
6x2-9x+2x-3
3x(2x-3)+1(2x-3)
(2x-3)(3x+1)
so
6x2-7x-3
now by mid term factorisation
we have to find a numbers Which When multipled give 6*-3=-18 and on adding gives -7
so they are -9 and 2
so we can write it as
6x2-9x+2x-3
3x(2x-3)+1(2x-3)
(2x-3)(3x+1)
Anonymous:
are u cracking 10th this time
Answered by
1
6 x square - 7 x - 3
6 x square + ( 2 - 9 ) x - 3
6 x square + 2x - 9 x - 3
2 x ( 3x + 1 ) - 3 ( 3 x + 1 )
( 3x + 1 ) ( 2 x - 3 )
hope it will help you.... ☺☺
6 x square + ( 2 - 9 ) x - 3
6 x square + 2x - 9 x - 3
2 x ( 3x + 1 ) - 3 ( 3 x + 1 )
( 3x + 1 ) ( 2 x - 3 )
hope it will help you.... ☺☺
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