Question

HELLO MATE PLEASE ZZZZZ SOLVE IT

Answer 1

Answer:

(1/sin²θ - sin⁴θ)

Step-by-step explanation:

I am replacing θ with A for the better understanding.

Important Formulas:

(i) (1/tanθ) = cotθ

(ii) (1/cotθ) = tanθ

(iii) sin²θ + cos²θ = 1.

(iv) 1 - sin²θ = cos²θ

Now,

$Given:(1+\frac{1}{tan^2A})(1+\frac{1}{cot^2A)}$

$=(1 + \frac{1}{cot^2A})(1 + tan^2A)$

$=(1+\frac{cos^2A}{sin^2A})(1 + \frac{sin^2A}{cos^2A})$

$=(\frac{sin^2A+cos^2A}{sin^2A})(\frac{cos^2A+sin^2A}{cos^2A})$

$=\frac{1}{sin^2Acos^2A}$

$=\frac{1}{sin^2A(1-sin^2A)}$

$=\frac{1}{sin^2A-sin^4A}$

Hope it helps!

Answer 2

Answer:

(1/sin²θ - sin⁴θ)

Step-by-step explanation:

hope this is helpful