Question

HELLO MATE
PLZ ANSWER
IF ONE OF THE ANGLES OF THE TRIANGLE IS 130°,THEN THE ANGLE BETWEEN THE BISECTOR OF TUE OTHER 2 ANGLES CAN BE
(A) 50°
(B) 65°
(C) 145°
(D) 155°
SOLVE WITH SUM
​

Answer 1

Answer:

B

Step-by-step explanation:

because half of 130 do divde of 130

Answer 2

Step-by-step explanation:

Consider a △ABC,such that ∠BAC=130

∘

and bisectors of ∠B and ∠C meet at O.

To find: ∠BOC

Now, in △ABC,

∠BAC+∠ABC+∠ACB=180

130+∠ABC+∠ACB=180 (Angle sum property)

∠ABC+∠ACB=50

2

1

(∠ABC+∠ACB)=25

∠OBC+∠OCB=25 (OB and OC bisect ∠ABC and ∠ACB)

Now, in △OBC,

∠OBC+∠OCB+∠BOC=180

25+∠BOC=180

∠BOC=155