Math, asked by ShuchiRecites, 1 year ago

Hello Mates!

Ques. In the given figure, <A = <C and AB = BC. Prove that triangles ABD is congruent to CBE.

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Answered by Anonymous

$\bf{\huge{Answer}}$

$@$

Answer in attachment:-

Here, Using Angle,Side and Angle Similarity Condition. in short form [ASA Similarly]

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TooFree: AA proves that the two triangles are similar but not necessary congruent.

TooFree: @Sujeetkumarray, you may want to add in "S" (since it is given that AB = BC) .. then by ASA .. both triangles are congruent.

Anonymous: Amazing

Prakhar2908: @Sujeetkumarray , ASA is a congruency condition not a similarity condition.

Prakhar2908: and Triangle ABD is congruent to Triangle CBE

Prakhar2908: You have inserted similarity sign between ABD and CBE instead of the congruent sign

Anonymous: oh!! Apology ... Please give me EDITING OPTION

Prakhar2908: Given.

Anonymous: Oh thank you

Prakhar2908: Edit your answer.

Answered by Prakhar2908

$\textbf{Thanks for asking the question!}$

$\underline{Concepts\ used : }$

=> Congruency of two triangles

=> Postulates of congruency

$\textit{Please refer to the attachment for detailed solution}$

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Anonymous: Superb.... fantastic... amazing... Answer

Prakhar2908: Thanks : )

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Hello Mates!Ques. In the given figure, <A = <C and AB = BC. Prove that triangles ABD is congruent to CBE.Don't spam because spamming don't effect anyone else but yourself.Have great future ahead!

Answers

Hello Mates!

Ques. In the given figure, <A = <C and AB = BC. Prove that triangles ABD is congruent to CBE.

Don't spam because spamming don't effect anyone else but yourself.

Have great future ahead!