Math, asked by questionbabaji79, 1 year ago

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Maths :::::::::::

RS.5500 amounts to 7975 in 5 years at simple interest. what will Rs.6200 amount to in 3 years at the same rate of interest

step by step explanation dedo

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Answers

Answered by deeksha7790
101
Heya mate here is your answer

____________________✌️❤️✌️

Here :

• Principal (P) = Rs. 5500

• Time (T)= 5 years

• Amount(A) = Rs. 7975

Therefore∴ SI = Amount - Principal

= > 7975 - 5500 = 2475=>7975−5500=2475

WeknowSI=

100

P×R×T

= > 2475 = \frac{5500 \times R \times 5}{100}=>2475=

100

5500×R×5

= > \frac{2475 \times 100}{5500 \times 5} = R=>

5500×5

2475×100

=R

= > R \: = \frac{2475 \times 100}{5500 \times 5}=>R=

5500×5

2475×100

= > \frac{2475}{275}=>

275

2475

= > R \: = \: 9=>R=9


R = 9 percent

\therefore∴ R = 9%

Now :

P = Rs.6200

R = 9% ( from above )

T = 3 years

\therefore∴ SI =

= > \frac{prt}{100} = \frac{6200 \times 9 \times 3}{100}=>

100

prt

=

100

6200×9×3

= > 62 \times 9 \times 3=>62×9×3

= > 558 \times 3=>558×3

= > 1674=>1674

Rs.1674

→ Amount = P + SI

= > 6200 + 1674=>6200+1674

= > 7874=>7874

Rs. 7874

therefore∴ Rs. 6200 will Amount to Rs. 7874 in 3 years at the same rate of interest.

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Answered by Sauron
98
\textbf{\underline{\underline{Answer :-}}}

\text{Rs.6200 will Amount to Rs.7874 in 3 yrs.}

\textbf{\underline{\underline{Explanation :-}}}

\textsf{\underline{\underline{Given : }}}

Rs.5500 amounts to = Rs.7975 in 5 years.

\textsf{\underline{\underline{To find :}}}

At the same rate of interest what will Rs.6200 amount to in 3 years.

\textsf{\underline{\underline{Solution :}}}

\textbf{\large{\underline{Case I}}}

Here,

Principal (P) = Rs.5500

Time (T) = 5 years

Amount = Rs.7975

As we know,

\starSimple Interest = Amount - Principal

\tt{\Rightarrow7975 - 5500}

\tt{\Rightarrow2475}

Simple Interest = Rs.2475

We know =

\sf{\implies \: SI = \dfrac{P \times R \times T }{100} }

\sf{\implies \: 2475 = \dfrac{5500 \times R \times 5}{100} }

\sf{\implies \: 2475 = \dfrac{55{\cancel{00}} \times R \times 5}{1{\cancel{00}}}}

\sf{\implies \: 2475 = 55 \times 5 \times R}

\sf{\implies2475 = 275 \times R}

\sf{\implies R = \dfrac{2475}{275} }

\sf{\implies R = 9}

{\boxed{\bigstar{\sf\:{Rate = 9\%}}}}

Now as we got the Rate of interest, we can find that how much will Rs.6200 amount to in 3 years.

\textbf{\large{\underline{Case II}}}

Principal (P) = Rs.6200

Rate (R) = 9% (From above)

Time (T) = 3 years

\sf{\implies \: SI = \dfrac{P \times R \times T }{100} }

\sf{\implies \: SI = \dfrac{6200 \times 9 \times 3 }{100} }

\sf{\implies \: SI = \dfrac{62{\cancel{00}} \times 9 \times 3}{1{\cancel{00}}}}

\sf{\implies \: SI =62 \times 27 }

\sf{\implies \: SI =1674}

{\boxed{\bigstar{\sf\:{SI = Rs.1674}}}}

\star Amount = Principal + SI

\sf{\implies \:1674 + 6200}

\sf{\implies \:7874}

{\boxed{\bigstar{\sf\:{Amount= Rs.7874}}}}

\therefore\text{Rs.6200 will Amount to Rs.7874 in 3 yrs.}

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