Question

hello, need the solution urgently.....guys please help​

Answer 1

21) b

22) d

Step-by-step explanation:

we just need to substitude the value of the factor in the given polynomial to get the answer

Answer 2

✰✰ ANSWER ✰✰

21. ${x}^{2}+kx-3=(x-3) (x+1)$

$⇢{x}^{2}+kx-3={x}^{2}+x-3x-3$

$⇢kx=x-3x$

$⇢kx=-2x$

$⇢[k+2]x=0$

☛$\large{\boxed{\bold{\bold{\purple{\sf{k=-2}}}}}}$

So,Option (b)-2 is correct..

_______________________

22. $\textbf{x+1=0}$

$⇢\textbf{x=-1}$

➜Putting x=-1

$⇢2{x}^{2}+kx=0$

$⇢2{(-1)}^{2}+k(-1)=0$

$⇢2(1)-1k=0$

$⇢2-1k=0$

$⇢-1k=0-2$

$⇢k=\cancel\dfrac{-2}{-1}$

☛$\large{\boxed{\bold{\bold{\green{\sf{k=2}}}}}}$

So,Option (d) 2 is Correct..