Question

Hello.. Please answer ​

Answer 1

If there're no real roots, then b²-4ac<0

Here a=1, b=-b and c=1

So b²-4<0

So b²>0

So option A

Hope it helped u ☺️

Answer 2

$\mathbb{\orange{SOLUTION}}$

If there are no real roots for any equation,

Then

$\boxed{\red{b^{2}-4ac<0}}$

=> (-b)²-4(1)(1)<0

=> b²-4<0

=>b²<4

=>b<±2

> ±b < 2

> |b|<2

option d