Question

Hello please help me

Answer 1

In the given figure we have

angle ABC = angle ADC (90° each)

BC = CD


To prove :- AC bisects angle BAD


Proof :-


In ∆ABC and ∆ADC, we have

angle ABC = angle ADC (given)

BC = CD (Given)

AC = AC (Common)


So we have a right angle, hypotenuse and a side equal.

So by RHS congruency rule,

∆ABC is congruent to ∆ADC

=> angle BAC = angle CAD (c.p.c.t)

Now,

angle BAC + angle CAD = angle BAD

but angle CAD = angle BAC

=> angle BAC + angle BAC = angle BAD

=> 2 BAC = angle BAD

=> angle BAC = 1/2 angle BAD

and angle CAD = angle BAC

=> angle CAD = 1/2 angle BAD


since, angle CAD and angle BAC are half of angle BAD, we can say that angle BAD is bisected by AC



Hence Proved :)

Answer 2

hey
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hope helped
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