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Please Help ! Question on turning effect of Force
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Explanation:
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Answer:
- The magnitude of the force P acting on the system is
Step-by-step Explanation:
Given:
- The beam is balanced [ Net torque is Zero ]
- A force of 8.1 N acts on the beam at the distance of 2 cm downward
- A force of 5.2 N acts on the beam at the distance of 6 cm downward
- A force of P acts on the beam at the distance of 2 cm upward
To Find:
- The magnitude of the force P
Formula Used:
- Magnitude of Torque = RFSin∅
We know that:
- The Net torque is equal to 0 so, the upward torque is balanced by the downward torque
Calculating the downward torque₁ :
- Torque₁ = RFSin∅
- Torque₁ = 2/100 × 8.1 × Sin(90)
- Torque₁ = 0.02 × 8.1 × 1
- Torque₁ = 0.162 Nm
Calculating the downward torque₂ :
- Torque₂ = RFSin∅
- Torque₂ = 6/100 × 5.2 × Sin(90)
- Torque₂ = 0.06 × 5.2 × 1
- Torque₂ = 0.312 Nm
Calculating total downward torque :
- Total downward torque = Torque₁ + Torque₂
- Total downward torque = 0.612 + 0.312
- Total downward torque = 0.924 Nm
Henceforth:
- The total downward torque is 0.924Nm which is equal to the upward torque
Calculating the force P acting upwards :
- Torque₃ = RFSin∅
- 0.924 = 2/100 × P × Sin(90)
- 0.924 = 0.02 × P × 1
- P = 0.924/0.02
- P = 46.2 N
Therefore:
- The magnitude of the force P is 46.2 N
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