Question

HELLO !!!



PLEASE SOLVE​

Answer 1

SOLUTION

Let the money invested in scheme A= Rs.x

& money invested in scheme B= Rs. y

Now schemes A and B offer Interest at the rate of 8% per annum and 9% per annum respectively and she received and annual Interest of Rs. 1860

This means 8% of x+9% of y= 1860

so,

.08x+.09y=1860..........(1)

Now if she interchange the amounts imvested in each scheme she will Rs. 20 more as an annual Interest.

That means 8% of y+9% of x= 1860+20

so,

.08y+.09x= 1880...........(2)

Now we solve (1) and (2) for x and y

and we get

x= 12000

y= 10000

So Money invested in scheme A= Rs.12000.

So Money invested in scheme A= Rs.12000.and money invested in scheme B= Rs.10000

Hope it helps ✔️❣️☺️

Answer 2

Question :-

Susan invested certain amount of money in two schemes A and B , which offers Interest at the rate of 8% per annum and 9% per annum respectively. She receives RS 1860 as annum Intrest . However , had she interchanged the amount of investment in two schemes , she would receive RS. 20 more as annum Intrest . How much money did she invested ?

Answer :-

As it's Given :-

▪️No of schemes = 2

▪️Rate of interest offered by scheme A = 8%

▪️Rate of interest offered by scheme B = 9%

▪️Annual Intrest received by her = RS. 1860

▪️Annual Intrest received by her when she exchanges the invested amount = Rs. 20 More

Now Let the amount invested in

▪️Scheme A be "x"

▪️And Scheme B be "y"

Then As

SI = (PRT)/100

Where

▪️P = Principle Amount

▪️R = Rate of interest

▪️T = Time period

When she invested "x" and "y" amount of money in A and B respectively..

→ 1860 = (x × 8 × 1)/100 + ( y × 9 × 1)/100

→1860 = 8x/100 + 9y/100

→ 0.8x + 0.9y = 1860 ....(i)

Now when she invested "y" and "x" amount of money in A and B respectively.

→1860 + 20 = ( y × 8 × 1)/100 + (x × 9 × 1)/100

→ 1880 = 8y/100 + 9x/100

→ 1880 = 0.9x + 0.8y ....(ii)

Now By 9 × (i) - 8 × (i)

7.2x + 8.1y = 16740

- 7.2x - 6.4y = - 15040

_______________________

1.7y = 1700

→ y = (1700) ÷ 1.7

→ y = 1000

Now by putting Value of y in equation (i)

→ 0.8x + 0.9(1000) = 1860

→0.8x + 900 = 1860

→ 0.8x = 1860 - 900

→ 0.8x = 960

→ x = (960) ÷ 0.8

→ x = 1200

So we have

Amount of money invested in Scheme A

= x

= 1200

Amount of money invested in Scheme B

= y

= 1000