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A shopkeeper gives book on rent for reading .She takes a fixed charge for first 2 days an additional charge for each day there after latika paid Rs 22 for a book kept for 6 days while anand paid Rs 16 for book kept for 4 days . Find each charge the charge for each extra day.
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Answered by
72
Fixed charge = x
Per day charge after day 2= y
Total Latika amount = 22rupee
Total Latika days = 6 days
Total Anand amount = 16rupee
Total Anand days = 4 days
Equation for Latika-
x + 4y = 22
Equation for Anand-
x + 2y = 16
Subtracting second equation from first-
x + 4y - x - 2y = 22 - 16
=> 2y = 6
=> y = 3
Put y in first equation
x + 4(3) = 22
=> x = 10
Thus fixed charge is 10 rupee and per day charge is 3 rupee
Per day charge after day 2= y
Total Latika amount = 22rupee
Total Latika days = 6 days
Total Anand amount = 16rupee
Total Anand days = 4 days
Equation for Latika-
x + 4y = 22
Equation for Anand-
x + 2y = 16
Subtracting second equation from first-
x + 4y - x - 2y = 22 - 16
=> 2y = 6
=> y = 3
Put y in first equation
x + 4(3) = 22
=> x = 10
Thus fixed charge is 10 rupee and per day charge is 3 rupee
Mayankjain121:
given earlier
Answered by
23
Hi there !!
Fixed charge = x [ 2 days ]
Extra charge = y [ additional for each 1 day ]
According to the question :-
x + 4y = 22 -----> [1]
x + 2y = 16 -----> [2]
Subtracting (1) - (2) , we get :-
x + 4y = 22
-
x + 2y = 16
---------------------------------
2y = 6
y = 6/2
y = 3
x + 2y = 16
x + 6 = 16
x = 10
Fixed charge = x = Rs 10
Extra charge = y = Rs 3
Fixed charge = x [ 2 days ]
Extra charge = y [ additional for each 1 day ]
According to the question :-
x + 4y = 22 -----> [1]
x + 2y = 16 -----> [2]
Subtracting (1) - (2) , we get :-
x + 4y = 22
-
x + 2y = 16
---------------------------------
2y = 6
y = 6/2
y = 3
x + 2y = 16
x + 6 = 16
x = 10
Fixed charge = x = Rs 10
Extra charge = y = Rs 3
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