Math, asked by helina28, 1 year ago

hello pls ans this q pls pls
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Answered by siddhartharao77
3

(2)

Given A≡ (t^2,2t) , B≡(1/t^2, -2/t), S≡(1,0).

We know that distance between the points (x1,y1) and (x2,y2) is given by

= > D = √(x2 - x1)^2 + (y2 - y1)^2.

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Now,

For SA, (x1,y1) = (1,0) and (x2,y2) = (t^2,2t).

Distance between the points SA = √(t^2 - 1)^2 + (2t - 0)^2

⇒ √t^4 + 1 - 2t^2 + 4t^2

⇒ √t^4 + 1 + 2t^2

⇒ √(t^2 + 1)^2

⇒ t^2 + 1.

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Now,

For SB, (x1,y1) = (1,0) and (x2,y2) = (1/t^2, -2/t)

Distance between the points SB = √(1/t - 1)^2 + (-2/t - 0)^2

⇒ √(1/t^2 + 1 + 2/t^2)

⇒ √(1/t + 1)^2

⇒ (1/t^2 + 1)

⇒ (1 + t^2)/t^2.

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Hence,

⇒ 1/SA + 1/SB

⇒ (1/t^2 + 1) + (t^2/t^2 + 1)

⇒ (1 + t^2)/(1 + t^2)

⇒ 1.




Hope it helps!



siddhartharao77: :-)
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