Question

hello pls answer this question

Answer 1

$\huge{HELLO DEAR}$
__________________________

Solution :- In triangle abc.

angle BAC is equal to 30 degree ,,,,angle abc is equal to 50 degree.

then angle ACB is equal to.
angle BAC + angle ACB + angle abc= 180.
( by angle sum property)

30°+ angle ACB+50°=180°
80°+ angle ACB=180°

angle ACB=100°.
since BCD is a straight line sum 180° .
in triangle in ECD.

angle EDC=40° .

angle ECD.is equal to 80° .
then angle CED is equal to 60 degree.

since a AEC is also a straight line.
then angle AED + angle CED =180° .
then angle AED =120° .
__________________________
===============================

$<marquee > HOPE ITS HELP YOU!!$
================================



__________(^^_^^)________

Sumit Tiwari from Azamgarh (up). ^_-