Question

Please solve this question with proper steps.

Answer 1

Angle A +Angle B +Angle C =180
Now 3AngleA=4AngleB
Angle B=(3/4)*AngleA
Also 3AngleA=6AngleC
AngleC=(3/6)Angle A
AngelA+3/4AngleA+3/6AngleA=180
Now take LCM
24AngleA+18AngleA+12AngleA=180*24
54AngleA=180*24
AngleA=80°
AngleB=(3/4)*AngleA
=60°
AngleC=180-(80+60)
=40°
Hope it helps
:)

Answer 2

Answer:

80°, 60°, 40°

Step-by-step explanation:

In ΔABC, 3∠A = 4∠B = 6∠C.

Let 3∠A = 4∠B = 6∠C = x.

(i)

∠A = x/3

(ii)

∠B = x/4

(iii)

∠C = 6/x.

Now,

We know that Sum of interior angles of a triangle = 180°.

⇒ ∠A + ∠B + ∠C = 180°

⇒ (x/3) + (x/4) + (x/6) = 180

⇒ 9x = 2160

⇒ x = 240°.

Therefore:

∴ ∠A = 80°

∴ ∠B = 60°

∴ ∠C = 40°

Hope it helps!