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Question :
Prove that, (cosec∅-cot∅)² = (1-cos∅)/(1+cos∅)
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Answered by
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Prove that :
(cosec∅-cot∅)² = (1-cos∅)/(1+cos∅)
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LHS :
(cosec∅ - cot∅)² .....(i)
we know that,
cosec∅ = 1/sin∅
cot∅ = cos∅/sin∅
Now put the above values in (i)
we get,
[1/sin∅ - (cos∅/sin∅)]²
Taking sin∅ as LCM,
We get,
[(1 - cos∅)/sin∅]²
=> (1-cos∅)²/sin²∅ .......[A]
RHS :
(1-cos∅)/(1+cos∅)
After rationalising,
(1-cos∅)/(1+cos∅) × (1-cos∅)/(1-cos∅)
=> (1-cos∅)²/[(1)² - (cos∅)²]
=> (1-cos∅)²/(1-cos²∅)....(ii)
Now, we also know that,
sin²∅ + cos²∅ = 1
So, sin²∅ = 1 - cos²∅
put this value in (ii),
=> (1-cos∅)²/sin²∅ ......[B]
_______________________
From [A] and [B],
LHS = RHS
Hence proved!
Answered by
7
hey mate please refer to the attachment
there is two methods ,,,short and long ,,u can see .
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