Question

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SOLVE:(X-A)(X-B)(X-C)...(X-Z)

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Answer 1

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Q:Solve:(X-A)(X-B)(X-C)......(X-Z)

${\boxed{\huge{\mathsf{Solution:-}}}}$
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Given that,

Solve:(X-A)(X-B)(X-C)......(X-Z)

Now, though the question seems to be tricky but its quiet easy!!

In the series, one term would also come(X-X) and the result of that term will be 0.

Thus, the rest of the terms multiplied with zero, the final answer turns out to be Zero(0).

Therefore,

(X-A)(X-B)(X-C)......(X-Z)=0

$\huge{\underline{\underline{\mathfrak{Hope It Helps!!}}}}$

Answer 2

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$(x - a)(x - b)(x - c).........(x - z) \\ \\ \implies \: (x - a) \times (x - b) \times (x - c)...... \times 0 \times (x - y)(x - z) \\ \\ \implies0$

We know that the product of Zero is Zero, in sequence we get (x-x) which is equal to zero. Multiplying the whole term with zero our final result will be Zero.

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