Question

hello there please anyone can tell me how can I solve maths questions with X values in denominator of two fractions so at the end I want to answer how can I take LCM

Answer 1

Answer:

63(x+6) + 72x = 3(x)(x+6)

divide by 3 full equation

21(x+6)  + 24x = x² + 6x

21x + 126 +24x =  x² + 6x

x² + 6x - 45x -126 = 0

x² - 39x -126 = 0

x²  - 42x +3x -126 = 0

x(x-42) + 3(x-42) = 0

(x - 42)(x + 3) = 0

x = 42 or x = -3

Step-by-step explanation:

Answer 2

hope this answer helps u..