Hello there......please help.......
Calculate the mass of iron which will be converted into its oxide Fe2O3,by the action of 18g of steam.(At.mass of Fe=56u,H=1u,O=18u).The reaction takes place according to the equation
3Fe+4H2O -> Fe3O4+4H2
No spam please....
Answers
Answered by
1
Explanation:
The reaction occurs as:
3Fe+4H
2
O→Fe
3
O
4
+4H
3
3Fe+4H2O→Fe3O4+4HMole ratio of reaction suggest
Mole of H
2
O
Mole of Fe
=
4
3
Mole of Fe =
18
18
×
4
3
Weight of Fe =
4
3
×56=42g
Similar questions