Hello users!!!
Plz solve the question given in the attachment...
Question no. 105 only
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Hey Mate !
Here is your solution :
Given,
=> ( a² + b² + c² ) = 280 ------- ( 1 )
=> ab + bc + ca = ( 9/2 ) --------- ( 2 )
Now,
=> ( a + b + c)² = a² + b² + c² + 2 ( ab + bc + ca )
=> ( a + b + c )² = 280 + 2 ( 9/2 )
=> ( a + b + c )² = 280 + 9
=> ( a + b + c )² = 289
=> ( a + b + c ) = √289
=> ( a + b + c ) = 17
Cubing both sides,
=> ( a + b + c )³ = ( 17 )³
=> ( a + b + c )³ = 4,913
The required answer is 4,913.
==============================
Hope it helps !! ^_^
Here is your solution :
Given,
=> ( a² + b² + c² ) = 280 ------- ( 1 )
=> ab + bc + ca = ( 9/2 ) --------- ( 2 )
Now,
=> ( a + b + c)² = a² + b² + c² + 2 ( ab + bc + ca )
=> ( a + b + c )² = 280 + 2 ( 9/2 )
=> ( a + b + c )² = 280 + 9
=> ( a + b + c )² = 289
=> ( a + b + c ) = √289
=> ( a + b + c ) = 17
Cubing both sides,
=> ( a + b + c )³ = ( 17 )³
=> ( a + b + c )³ = 4,913
The required answer is 4,913.
==============================
Hope it helps !! ^_^
Sanskriti141:
Thanks a lot bro
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