hellow frnds
plz solve the problem
step by step. and gd night
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hey mate
refer to attachment
refer to attachment
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laba46:
If you write tan @and cot @ as the ratio of sin and cos it will be very easy .
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hey
1/1+tan^2a +1/1+cot^2a
we know that
1+tan^2a= sec^2a. 1+cot^2a=cosec^2a
therefore
1/sec^2a +1/cosec^2a
=cos^2a + sin^2a. (sin^2a = 1/cosec^2a. & cos^2a = 1/sec^2a)
=1. (cos^2a + sin^2a = 1)
1/1+tan^2a +1/1+cot^2a
we know that
1+tan^2a= sec^2a. 1+cot^2a=cosec^2a
therefore
1/sec^2a +1/cosec^2a
=cos^2a + sin^2a. (sin^2a = 1/cosec^2a. & cos^2a = 1/sec^2a)
=1. (cos^2a + sin^2a = 1)
If you write tan @ and cot@ as the ratio of sin and cos it would be very easy.
k thanks
thnk you
bbarik Do it as I said , may be it will be very easy.
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