Question

Help!!!!!........................

Answer 1

Hey user here is your answer.......

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◆Let the theta be A

◆Cos^2A/sinA-CosecA+SinA

◆Cos^2A/SinA-1/SinA+SinA ( CosecA=1/sinA)

◆Take L.C.M

◆Cos^2A-1+Sin^2A/SinA

◆1-1/sinA

=0

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⭐️Hope it helps you⭐️

✌️ Rohan( Maths aryabhatta)✌️

Answer 2

Sol : ( cos²Θ / sinΘ ) - cosecΘ + sinΘ

     cos²Θ - cosecΘ x sinΘ + sin²Θ
 =  --------------------------------------------
                    sinΘ

    cos²Θ+sin²Θ - 1
= -------------------------  { cosecΘ x sinΘ = 1 }
         sinΘ

        1 - 1
= -----------------  { sin²Θ + cos²Θ = 1}
         sinΘ

= 0 / sinΘ

= 0.

Answer : ( D ) 0.
 
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