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answer the 13 question
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Step-by-step explanation:
ABC is a triangle other than an equilateral triangle.
Contruct the Triangle ABC Such that the sides AB AD and BD are Equal
Proof:
Since AB = AD = BD
/_ 1 = /_ 3 = /_ 4
Now
BC is the largest side, the angle Opp to it is /_ BAC
/_ BAC = /_ 1 + /_ 2
/_ BAC = 60^ + /_ 2
since 60^ = 2/3 (90^)
/_ BAC = 2/3(90^)+/_2
=> /_ BAC >2/3(90^)
HENCE PROVED
Therefore in a triangle, other than an equilateral triangle, the angle opposite to the longest side is greater than (2/3)rd of a right angle.
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