help anyone please ?
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Heya
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Cos ( 90 + x ) = - Sin x
And Sin ( 90 + x ) = Cos x
1) Cos ( 135° ) = Cos ( 90 + 45 )
= -Sin ( 45 ) = -1/√2
2) Sin ( 135° ) = Sin ( 90 + 45 )
= Cos ( 45° ) = 1/√2
______________________________
Cos ( 90 + x ) = - Sin x
And Sin ( 90 + x ) = Cos x
1) Cos ( 135° ) = Cos ( 90 + 45 )
= -Sin ( 45 ) = -1/√2
2) Sin ( 135° ) = Sin ( 90 + 45 )
= Cos ( 45° ) = 1/√2
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