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Given, cos(90-A)/sinA = sin(90-A)/cosA
Taking LHS :
cos(90-A)/sinA = sinA/sinA (because cos(90-©)=sin© )
= 1 ------------------(1)
Now, Taking RHS :
sin(90-A)/cosA = cosA/cosA (because sin(90-©)=cos© )
= 1 ----------------------(2)
So, from (1)&(2)
LHS = RHS Hence proved
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