Question

help!!??????
Find the roots of the above quadratic equation by factorisation method.

Answer 1

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$2( \frac{x - 1}{x + 3} ) - 7( \frac{x + 3}{x - 1} ) = 5 \\ or. \: \frac{2 {(x - 1)}^{2} - 7 {(x + 3)}^{2} }{(x - 1)(x + 3)} = 5 \\ or. \: 2( {x}^{2} - 2x + 1) - 7( {x}^{2} + 6x + 9) = 5( x - 1)(x + 3) \\ or. \: 2 {x}^{2} - 4x + 2 - 7 {x }^{2} - 42x - 63 = 5( {x}^{2} - x + 3x - 3) \\ or. \: - 5 {x}^{2} - 46x - 61 = 5 {x }^{2} + 10x - 15 \\ or. \: 10 {x}^{2} + 56x + 46 = 0 \\ or. \: 10 {x}^{2} + 10x + 46x + 46 = 0 \\ or. \: 10x(x + 1) + 46(x + 1) = 0 \\ or. \: (x + 1)(10x + 46) = 0 \\ \\ since \: x \: is \: not \: equal \: to \: - 1 \\ \\ so. \: x = - \frac{46}{10} = - 4.6$
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