Question

help guys please immediately​

Answer 1

Step-by-step explanation:

Given :-

n(A) = 20

n(B) = 28

n(AUB) = 36

To find :-

Find the value of n(AnB) ?

Solution:-

Given that

n(A) = 20

n(B) = 28

n(AUB) = 36

We know that

n(AUB) = n(A)+n(B)-n(AnB)

=> n(AnB) = n(A)+n(B)-n(AUB)

On Substituting these values in the above formula then

=> n(AnB) = 20+28-36

=> n(AnB) = 48-36

=> n(AnB) = 12

Therefore, n(AnB) = 12

Answer:-

The value of n(AnB) for the given problem is 12

Used formulae:-

• n(AUB) = n(A)+n(B)-n(AnB)
• This formula is known as Fundamental Theorem on sets.
• n(A) = Number of elements in the set A
• n(B) = Number of elements in the set B
• n(AUB) = Number of elements in the set AUB
• n(AnB) = Number of elements in the set AnB