Question

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Answer 1

$\large\rm { (\frac{-7}{8} p^{2} qr)(5pq^{2})(8r^{2})}$

$\large\rm { = \frac{-7}{8} p^{3} q^{3} r \times 5 \times 8r^{2}}$

$\large\rm { = \frac{-7}{8} p^{3} q^{3} r^{3} \times 5 \times 8}$

$\large\rm { = \frac{-35}{8} p^{3} q^{3} r^{3} \times 8}$

$\large\rm { = \dfrac{ 35}{ \cancel{8}} (pqr)^{3} \times \cancel{8}}$

$\large\rm { = -35(pqr)^{3}}$

Answer 2

Answer:

$(8−7p2qr)(5pq2)(8r2)</p><p>\large\rm { = \frac{-7}{8} p^{3} q^{3} r \times 5 \times 8r^{2}}=8−7p3q3r×5×8r2</p><p>\large\rm { = \frac{-7}{8} p^{3} q^{3} r^{3} \times 5 \times 8}=8−7p3q3r3×5×8</p><p>\large\rm { = \frac{-35}{8} p^{3} q^{3} r^{3} \times 8}=8−35p3q3r3×8</p><p>\large\rm { = \dfrac{ 35}{ \cancel{8}} (pqr)^{3} \times \cancel{8}}=835(pqr)3×8</p><p>\large\rm { = -35(pqr)^{3}}=−35(pqr)3</p><p>$