help help anyone ? due today @2:30
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(-√3/2-i1/2)^12 = (cos 7π/6 + i sin 7π/6)^12
= ( cis 7π/6) ^12
By Demoivre Theorem,
= cis ( 7π/6*12) = cis ( 14π )
= cos 14π + i sin 14π = 1+ 0.i = 1
Hope this helps you !
= ( cis 7π/6) ^12
By Demoivre Theorem,
= cis ( 7π/6*12) = cis ( 14π )
= cos 14π + i sin 14π = 1+ 0.i = 1
Hope this helps you !
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