Question

HELP HELP ASAP I NEED THE ANSWER TODAY BECUASE IT IS DUE TODAY. HELP ME PLEASE . ASAP . THERE IS A PICTURE OF MY ASSIGNMENT

Answer 1

Hey !

Given,

Point, P(x1,y1) = (-3,2)

Slope, m = -3/4

(i) Plot the graph.

Step-1: Plot point P

Step-2: According to the given slope, rise mand run to the other point Q.

Step-3: Draw a line joining the P and Q.

$\huge{\fbox{\mathbf{Slope = \dfrac{rise}{run}}}}$



Given, $\rm{Slope}= \dfrac{-3}{4}$

=> Rise = -3 ; Run = 4

Rise y1 by -3 => y1 + Rise =2 + (-3) = 2 -3 = -1 (Let it be denoted by a)

a(x1,-1) = a(-3,-1) = (xn, yn)

While rising, x- coordinate value doesn't changes as we move over y-axis.

Now,

Coordinates of New point a(-3,-1)

xn = -3 ; yn = -1



From a ,run xn by 4= xn+Run -3+ 4= 1 (Let it be denoted by b)

b(-1, yn) = b(1, -1)

While running, y- coordinate value doesn't changes as we move over x-axis.

Here, Q is point b.

=> Q(1, -1)

Now connect P and b,

to get the line of equation y = (-3/4)x+c

The graph of the line for given point is shown in the attachment.



(ii) Using the two points P and Q to validate the slope

We have,

Slope of the equation given two points (x1,y1) and (x2,y2) is given as :

$\huge{\fbox{\mathbf{Slope, m = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}}}$

Substitute the values

P(-3,2) = (x1,y1) ; Q = (1,-1) = (x2,y2)

$\rm{Slope} = \dfrac{-1-2}{1-(-3)} = \dfrac{-3}{4}$



Kind Note : The attachment (Image) or the answer is neither copied from textbook nor taken from other internet sources.



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