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Test phythagorous theorem,
3^2+4^2=5^2
9+16=25
25=25
=) B=90°
Area=1/2×4×3
=6units
Pls mark it as brainliest
Answered by
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Answer:
Angle B = 90°
Step-by-step explanation:
AB = 3 units
BC = 4 units
AC = 5 units
Hence, AC is the longest side
AC^2 = AB^2 + BC^2
5^2 = 3^2 + 4^2
25 = 9 + 16
25 = 25
This satisfies the Pythagoras theorem.
Therefore, angle B is equal to 90°
Now,
Area of the ∆ABC = 1/2 × base × height
Area of the ∆ABC = 1/2 × 4 × 3
Area of the ∆ABC = 6 sq. units
HOPE IT HELPS !!!
If it does, then do mark my answer as brainliest...
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