Question

how many term are there in an AP whose first term and fiveth term are -14 and 22and their sum of the term is 40​

Answer 1

Answer:

hope this will help

Step-by-step explanation:

Solution :

Let first term and common difference of AP be a and d, respectively

Given , ` S_(75) = 2625`

` Rightarrow 2625 = 75/2 [ 2.a + (75-1)d]`

` Rightarrow 2625.2 = 75 [2a+ 74d] `

35.2 =2 [a + 37d ]

a + 37b = 35

a + ( 38 +1 ) d = 35

`T_(38) = 35`

Answer 2

Answer:

Here is your Answer brother

let the first number X & second be y

Now

\begin{gathered}x + y = 22 \\ x - y = 2 \\ \\ add \: the \: eqution \\ 2x = 24 \\ x = \frac{24}{2} = 12 \\ put \: the \: value \: in \: eqution \: (1) \\ 12 + y = 22 \\ y = 22 - 12 \\ y = 10 \: ans\end{gathered}

x+y=22

x−y=2

addtheeqution

2x=24

x=

2

24

=12

putthevalueineqution(1)

12+y=22

y=22−12

y=10ans