Question

help in question:-the number of roots of the quadratic equation 8sec2 O(thitaa)-6secO(thitaa)+1=0 is​

Answer 1

Answer:

hey mate .... here is your answer

Step-by-step explanation:

let thitaa=x

:. our equation will be

$8 {x}^{2} - 6x + 1 = 0$

$8 {x}^{2} - 4x - 2x + 1 = 0$

$4x(2x - 1) - 1(2x - 1) = 0$

$(4x - 1)(2x - 1) = 0$

hence our factors are (4x-1) and (2x-1)

$4x - 1 = 0$

$4x = 1$

$x = \frac{1}{4}$

and

$2x - 1 = 0$

$2x = 1$

$x = \frac{1}{2}$

hence roots are 1/4 and 1/2

therefore no. of roots=2

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