Help integrated
∫1/X2+6x dx
doraemondorami2:
Is it 1/x^2
1/xsquared
ok
1/xsquared+6x
its ok
thanks again
Do u have any doubt?
yes surface integrals ∫ ∫ s 4X dy-3y dzdx+2z dxdy
what i can't understand what is ur doubt .Please can u explain me in detail.
Answers
Answered by
1
∫(1/x^2 + 6x)dx = ∫1/x^2 dx + ∫6x dx
= -1/x + 3x² + c (where c is integral constant)
= -1/x + 3x² + c (where c is integral constant)
Answered by
1
∫1/x² + 6x dx = ∫1/x² dx + ∫ 6x dx
= -1/x +6 ∫x dx +C1
= -1/x + 6 x²/2 +C1 + C2
= -1/x + 3x² + C
= -1/x +6 ∫x dx +C1
= -1/x + 6 x²/2 +C1 + C2
= -1/x + 3x² + C
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