Question

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Two circles with centres O and P intersect each other at A
and B. Prove that the line OP bisects the common chord
AB at right angles.​

Answer 1

Answer:

In triangle AOP and BOP

\_AOP=\_BOP

(If 2 circles intersect at 2 points, their centres lie on the perpendicular bisector of the common chord)

OP=OP (common)

AP=BP (radii of circle)

Therefore, ∆AOP ≈ ∆BOP (by RHS congruency)

AO=BO (by CPCT)

Step-by-step explanation:

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Answer 2

Answer:

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