Question

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Answer 1

Step-by-step explanation:

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Answer 2

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$The \: sum \: of \: the \: integral \: parts = 4 + 2 = 6.$

$LCM \: of \: the \: denominators \: 6 \: and \: 3 = 6.$

$∴The \: sum \: of \: the \: fractional \: parts = \frac{1}{6} + \frac{1}{3}$

$= \frac{1 \times (6 \div 6) + 1 \times (6 \div 3)}{6}$

$= \frac{1 \times 1 + 1 \times 2}{6}$

$= \frac{1 +2 }{6}$

$= \frac{3}{6} = \frac{1}{2}$

$∴ \: The \: sum \: of \: the \: given \: fractions = 6 + \frac{1}{2} = 6 \frac{1}{2}$