help me 50 point solve also not only answer
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sehhhh:
iit level question hai
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3 + log10 x = 2 log10 y
or, 3 log10 10 + log10 x= 1og10 y2 [since log10 10 = 1]
or. log10 103 + log10 x = log10 y2
or, log10 (103 ∙ x) = log10 y2
or, 103 x = y2
or, x = y2/1000, which gives x in terms y.
I guess
or, 3 log10 10 + log10 x= 1og10 y2 [since log10 10 = 1]
or. log10 103 + log10 x = log10 y2
or, log10 (103 ∙ x) = log10 y2
or, 103 x = y2
or, x = y2/1000, which gives x in terms y.
I guess
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Hope it helps you dear........xD
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