help me..............
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Hi !
Solution :-
From LHS
=> 2cos²¢ + 3cos¢ = 2
=> 2cos²¢ + 3cos¢ - 2 = 0
=> 2cos²¢ + 4cos¢ - cos¢ - 2 = 0
=> 2cos¢ ( cos¢ + 2) - 1 ( cos¢ + 2) = 0
=> (2cos¢ - 1) ( cos¢ + 2) =0
cos¢ + 2 = 0
cos¢ = - 2 ( neglecting )
now ,
=> 2cos¢ - 1 = 0
=> cos¢ = 1 /2
since , cos¢ = cos60°
¢ = 60 °
Hence, cos3¢ = cos3 * 60 ° = cos180° = 0
since , cos3¢ = 0 Answer ✔
______________________
Hope this helps !!
@Rajukumar111
Solution :-
From LHS
=> 2cos²¢ + 3cos¢ = 2
=> 2cos²¢ + 3cos¢ - 2 = 0
=> 2cos²¢ + 4cos¢ - cos¢ - 2 = 0
=> 2cos¢ ( cos¢ + 2) - 1 ( cos¢ + 2) = 0
=> (2cos¢ - 1) ( cos¢ + 2) =0
cos¢ + 2 = 0
cos¢ = - 2 ( neglecting )
now ,
=> 2cos¢ - 1 = 0
=> cos¢ = 1 /2
since , cos¢ = cos60°
¢ = 60 °
Hence, cos3¢ = cos3 * 60 ° = cos180° = 0
since , cos3¢ = 0 Answer ✔
______________________
Hope this helps !!
@Rajukumar111
garudman:
great
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