Math, asked by idk56, 1 year ago

help me answer this.​

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Answered by vishaljain30
0

let the values be x,x-20,x-40,......,x-120 respectively

this is an AP where a=x,l=(x-120),n=7

sum=n/2(a+l)

700=7/2(x+x-120)

=7(x-60)

7x-420=700

7x=1120

x=160

the AP is 160,140,120,100,80,60,40.

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