Question

help me as fast as u can please​

Answer 1

Given:-

• $\sf Length \:of \:the \:rectangule(l) =60\:cm$
• $\sf Breadth \:of \:the \:rectangule(b) =40\:cm$
• $\sf Side \:of \:the \:square(a) =15\:cm$

Area of shaded region :-

${\pmb {\green {\boxed{\boxed {\orange {Area\: of\: shaded\: region = area \:of\: rectangle - area\: of\: square}}}}}}$

$\sf \longrightarrow Area \:of \:shaded \:region = l\times b - {a}^{2}$

$\sf \longrightarrow Area\: of \:shaded\: region=60 \times 40-{(15)}^{2}$

$\sf \longrightarrow Area\: of \:shaded\: region=240-225$

${\longrightarrow{\pink {\boxed {\boxed {\purple {\mathfrak {Area\: of\: shaded\: region =15\:{cm}^{2}}}}}}}}$

${\underbrace {\overbrace{\red {\underline {\overline{\red {\bf {\therefore The\: area\: of\: shaded\: region\: is\: 15\:{cm}^{2}}}}}}}}}$

Answer 2

Answer:

Given:-

\sf Length \:of \:the \:rectangule(l) =60\:cm Lengthoftherectangule(l)=60cm

\sf Breadth \:of \:the \:rectangule(b) =40\:cm Breadthoftherectangule(b)=40cm

\sf Side \:of \:the \:square(a) =15\:cm Sideofthesquare(a)=15cm

Area of shaded region :-

{\pmb {\green {\boxed{\boxed {\orange {Area\: of\: shaded\: region = area \:of\: rectangle - area\: of\: square}}}}}}

Areaofshadedregion=areaofrectangle−areaofsquare

Areaofshadedregion=areaofrectangle−areaofsquare

\sf \longrightarrow Area \:of \:shaded \:region = l\times b - {a}^{2} ⟶Areaofshadedregion=l×b−a

2

\sf \longrightarrow Area\: of \:shaded\: region=60 \times 40-{(15)}^{2}⟶Areaofshadedregion=60×40−(15)

2

\sf \longrightarrow Area\: of \:shaded\: region=240-225 ⟶Areaofshadedregion=240−225

{\longrightarrow{\pink {\boxed {\boxed {\purple {\mathfrak {Area\: of\: shaded\: region =15\:{cm}^{2}}}}}}}}⟶

Areaofshadedregion=15cm

2

{\underbrace {\overbrace{\red {\underline {\overline{\red {\bf {\therefore The\: area\: of\: shaded\: region\: is\: 15\:{cm}^{2}}}}}}}}}

∴Theareaofshadedregionis15cm

2