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as we know ,
< PAB = < ABC
so , < PAB = 30° = < ABC = x
hence , x = 30°
and also we know that , < QAC = < ACB
so , < QAC = 20° = < ACB = y
hence , y = 20°
and as a rule < PAQ = 180°
so ,
< PAB + < BAQ = < PAQ
30° + ( z + 20° ) = 180° [ < BAQ = z + 20° and < PAQ = 180° ]
50° + z = 180°
z = 180° - 50°
z = 130°
hence , x = 30°
y = 20°
z = 130°
I hope this will be help you
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