Question

help me fast plzzzzz

Answer 1

1) 1/(root2+root3)-root4     1/(root2+root3)-root4*root2+root3+root4/root2+root3+root4(multiplying it  with both numerator and denominator)using the identity (a+b)(a-b)=a^2-b^2 in the denominator
root 2+root 3+root4/(root 2+root 3)^2-(root 4)^2root 2+root 3+root 4/(root 2)^2+2(root 2)(root 3)+(root 3)^2-4root 2+root 3+root 4/2+2 root2 root3+3-4root 2+root 3+root 4/1+ 2 root 2 root 3do the same thing by multiplying root 2 root 3 from the
denominator so it becomes rational 2)  (root 3+root 2/root 3-root 2)^2      (root 3)^2+2 root 3 root 2+(root 2)^2/(root 3)^2-2 root 3 root 2+(root 2)^2      3+2 root 3 root 2+2/3-2 root 3 root 2+2       5+ 2 root 3 root 2/5 -2 root 3 root 2           (root 3-root 2/root 3+root 2)^2      (root 3)^2-2 root 3 root 2+(root 2)^2/(root 3)^2+2 root 3 root 2+(root 2)^2      3-2 root 3 root 2+2/3+2 root 3 root 2+2       5- 2 root 3 root 2/5+2 root 3 root 2  
       5+ 2 root 3 root 2/5 -2 root 3 root 2 +5- 2 root 3 root 2/5+2 root 3 root  2   use identity in the denominator and you will find your answer
 
3) 2 root 25*2 *3 root 4*8*4 root 9*2
    10 root 2*6 root 8*12 root 2     120 root 2*6 root 4*2     120 root 2*12 root 2      1440 root 2

4)1/1.414+3.141    (substitute and find the lcm and add it...as you add normal fractions) 5)(i) (see in the attachment below and follow the same steps for 5(ii)6(A) root 9+root 16   (b)root 3*root3    (c)root 16/root4