how to factorise : 6ab - b2 + 12ac - 2bc
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6ab+12ac-b2-2bc
=6a(b+2c)-b(b+2c)
=(b+2c)(6a-b)
=6a(b+2c)-b(b+2c)
=(b+2c)(6a-b)
Answered by
5
6ab - b2 + 12ac - 2bc = 6a (b +2c ) - b(b+2c) = (b +2c)(6a-b)
First, split the middle term, and you get (b +2c ) as common in both the terms ..
First, split the middle term, and you get (b +2c ) as common in both the terms ..
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