help me find angle ACB in this diagram
Attachments:
Answers
Answered by
1
Answer:
80°
please mark me as brainliest
Answered by
0
Answer:
∆AOB is a isosceles triangle so angle OBA=40° and angle AOB = 100°
the angle subtended by a chord to the center is twice the angle subtended at the another side of a circle
so angle ACB = 100/2 =50°
Similar questions