Question

help me for this fast plz​

Answer 1

Answer:

use this formula ...

↕↕↕↕↕↕↕↕↕↕↕↕

(a + b + c)2 = a2 + b2 + c2 +2ab+2bc +2ca. 6. (a + b + c)3 = a3 + b3 + c3+3a2b+3a2c + 3b2c +3b2a +3c2a +3c2a+6abc.

(hope it's helpful) ❤

Answer 2

GIVEN:-

• without actually calculating the cubes find the value of $\sf{-17^3+(13)^3+(4)^3}$

As we know that if a+b+c=0 then $a^3+b^3+c^3=3abc$.

So,

$\sf{a=-17}$

$\sf{b=13}$

$\sf{c=4}$

$\sf\blue{a+b+c=0=-17+13+4=0}$

so,

$\sf\blue{a^3+b^3+c^3=3abc}$

$\sf\red{3(-17)(13)(4)= -2652}$

So, The value is -2652.

EXTRA INFORMATION:-

• $(a+b)^2=a^2+b^2+2ab$

• $(a-b)^2=a^2-2ab+b^2$

• $a^3+b^3=(a+b)(a^2-ab+b^2)$