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cot A=8,find sin A and sec A
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Answer:
cot A = 8/1 =b/p
so by pythagorus theorm
H^2 =P^2+B^2
H^2= 1^2 +8^2
H^2=1+64=65
H=√65
SinA =p/h= 1/√65
sec A =h/b =√65/8
Step-by-step explanation:
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