Math, asked by uvcfhj, 1 year ago

HELP ME GENUS PLEASE HELP... *SOLVE*

Attachments:

Answers

Answered by khushiwarjurkar
2

As x^1/2 = √x

4×√1/0.81( √0.81+√0.81^3)

4×1/0.9 (0.9+0.729)

4×1.11 (1.629)

4.44 (1.629)

7.232


Hope it helps you ....




uvcfhj: sorry but wrong
khushiwarjurkar: Oh sorry misread the -'ve power
khushiwarjurkar: I'll correct it...
khushiwarjurkar: Now??
uvcfhj: ok
Answered by pratyush4211
10
4 \times {0.81}^{ \frac{ - 1}{2} } ( {0.81}^{ \frac{1}{2} } + {0.81}^{ \frac{3}{2} } )

We know That

x^-a=1/x^a

So,

4 \times ( \frac{1}{0.81}) {}^{ \frac{1}{2} } (0.81 {}^{ \frac{1}{2} } + 0.81 {}^{ \frac{3}{2} } )

We know If x^1/a=a√x

4 \times \sqrt{ \frac{1}{0.81} } ( \sqrt{0.81} + \sqrt{{0.81}^{3}} ) \\ \\

81=9×9

0.81=0.9×0.9

4 \times \frac{1}{0.9} (0.9 + 0.729) \\ \\ 4 \times \frac{1}{ \cancel{0.9}} \times \cancel{1.629} \\ \\ 4 \times 1.81 \\ \\ =7.24

\boxed{\mathbf{\huge{Answer=7.24}}}

pratyush4211: is it right
uvcfhj: yes but i asked this que in 8th class and now i am in 9th
sivaprasath: In bracket , [0.81^{-1/2} + 0.81^{-3/2}] right,. not ^{-1/2} ???
sivaprasath: 3/2**
Similar questions