Question

Help Me Guys...✌️

First Answer Will Be Brainlest....
^_^✌️✌️❣️❣️

Answer 1

radius of circle = 15 cm

since the angle subtended at the centre is
equal to 60 °

then ,

length of chord = radius of circle= 15 cm

so now the formed triangle inside the circle will be a equilateral triangle.

area of triangle AOB = √3/ 4 ( r)^2

= (1.73 ×( 15)^2)/ 4 = 97.31

area of minor segment

= area of corresponding sector - area of triangle (AOB)

= (60/360) πr^2 - Ar of triangle AOB

=( 1 ×3.14×225)/ 6 ) - 97.31

= 20.44 cm^2

area of major segment

= area of circle - area of minor segment

= πr^2 - 20.44 cm^2

= 3.14 × (15)^2 - 20.44

= 686.06 cm^2

Answer:
________

are of minor segment= 20.44 cm^2 AND area of major segment= 686.06 cm^2

Answer 2

Given, radius r = 15 cm, θ = 60°.

We know that Area of an Equilateral triangle = (√3/4) * (Side)^2.

(i)

Area of ΔOAB:

⇒ (√3/4) * (15)^2

⇒ (√3/4) * 225

⇒ 1.73 * 56.25

⇒ 97.31 cm^2.

(ii)

Area of sector OAPB:

⇒ (θ/360°) * πr^2

⇒ (60/360) * (3.14) * (15)^2

⇒ (1/6) * 3.14 * 225

⇒ 117.75 cm^2.

(iii)

Area of the minor segment APB = (Area of sector OAPB) - (Area of ΔOAB)

⇒ 117.75 - 97.31

⇒ 20.44 cm^2.

(iv)

Area of the major segment = (Area of circle) - (Area of minor segment)

⇒ (πr^2) - (20.44)

⇒ (3.14 * 15^2) - (20.44)

⇒ 706.5 - 20.44

⇒ 686.06 cm^2.

Therefore:

⇒ Area of minor segment = 20.44 cm^2.

⇒ Area of major segment = 686.06 cm^2.

Hope it helps!