Question

help me guys please help ​

Answer 1

Answer:

x = 50°

Step-by-step explanation:

Here,

x + 10 + 2x + 20 = 180° [Since Co-interior angles of parallel lines]

=> 3x + 30 = 180

=> 3x = 180 - 30

=> 3x = 150

$= > x = \frac{150}{3}$

=> x = 50° (Ans)

Answer 2

       $\underline{\bold{Solution:}}$

       $\text{We know that angles on the same side of the transversal are supplementary}$

$\implies PQ\parallel RS \text{ and }AB \text{ as the transversal}$

       $x + 10 + 2x + 20 = 180^{o}$

       $\text{Simplifying...}$

$\implies 3x + 30 = 180^{o}$

       $\text{Transposing 30 to R.H.S}$

$\implies 3x = 180 - 30$

       $\text{Simplifying...}$

$\implies 3x = 150^{o}$

       $\text{Transposing 3 to R.H.S}$

$\implies x = \dfrac{150}{3}$

       $\text{Simplifying...}$

$\implies \boxed{x = 50^{o} }$