Help me in solving this sum
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Step-by-step explanation:
let 2 digit no. be=x , so x+x=6, if 8 added x+x=6+8, ie. 2x =14, x=14\2, x=7
hope its correct
Manraj1011:
ty
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IT'S QUITE SIMPLE. FOLLOW MY STEPS GIVEN BELOW : -
LET, THE THE DIGIT AT UNIT'S PLACE BE 'x'
AND THE DIGIT AT TEN'S PLACE BE 'y'
THEREFORE,
THE TWO DIGIT NUMBER = 10y + x
AND THE NUMBER OBTAINED BY REVERSING THE DIGITS = 10x + y
HENCE FROM FIRST CONDITION,
x + y = 6 _____ 1.
AND FROM SECOND CONDITION,
10y + x + 8 = 10x + y
10y - y + x - 10x = -8
9y - 9y = -8 ____ 2.
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